【AE教程】文字特效合集
1parsec:
p14的表达式:
freq = 1; decay = 25; duration = 0.30; retard = textIndex*thisComp.frameDuration*1; t = time - (inPoint + retard); startVal = 【100,100,100】; endVal = 【0,0,0】; if (t < duration){ linear(t,0,duration,startVal,endVal); }else{ amp = (endVal - startVal)/duration; w = freq*Math.PI*2; endVal + amp*(Math.sin((t-duration)*w)/Math.exp(decay*(t-duration))/w); }
【回复】回复 @Henry1Song :[喜极而泣] 我刚刚试了下 中括号的【【】】全半角不太对没法运行 改这样就好了
freq = 1;
decay = 25;
duration = 0.30;
retard = textIndex*thisComp.frameDuration*1;
t = time - (inPoint + retard);
startVal = 【100,100,100】;
endVal = 【0,0,0】;
if (t < duration){
linear(t,0,duration,startVal,endVal);
}else{
amp = (endVal - startVal)/duration;
w = freq*Math.PI*2;
endVal + amp*(Math.sin((t-duration)*w)/Math.exp(decay*(t-duration))/w);
}
【回复】回复 @Henry1Song :[无语]应该是b站评论把中括号全改成中文的了 把【100,100,100】和【0,0,0】的中括号 改成英文的中括号运行就行
【回复】已经整理好了,这里全部都有https://www.bilibili.com/read/cv19036747
好大一朵小清新:
P1的mov链接:https://pan.baidu.com/s/19mGQohyEr5cOaOVsGuHeAQ
提取码:a01a
【回复】https://www.bilibili.com/read/cv18831114?spm_id_from=333.999.0.0
一缕茶烟透碧纱i:
P28 P26表达式
delay = .1;
myDelay = delay*textIndex;
t = (time - inPoint) - myDelay;
if (t >= 0) {
freq =3;
amplitude = 40;
decay = 12.0;
s = amplitude*Math.cos(freq*t*2*Math.PI)/Math.exp(decay*t);
【s,s】
}
else {
value
}
【回复】delay = .1;
myDelay = delay*textIndex;
t = (time - inPoint) - myDelay;
if (t >= 0) {
freq =3;
amplitude = 40;
decay = 12.0;
s = amplitude*Math.cos(freq*t*2*Math.PI)/Math.exp(decay*t);
【s,s】
}
else {
value
}
【回复】回复 @bblueeeee :说明表达式添加的位置不对,是在 效果三角形-选择器-表达式-展开表达式选择器-数量 中添加,而不是位置上
【回复】回复 @xx_channel :s,s 那个符号显示不出来,,,,,改为英文输入法点同样的符号键就对了
6ach1sism:
p16的笔刷素材链接 链接: https://pan.baidu.com/s/1rR0k8qFBl2a9wy2VvzsU7A 提取码: 6sk5
【回复】https://www.bilibili.com/read/cv18831114?spm_id_from=333.999.0.0
【回复】回复 @tinby :对的呀 我领取了~自己做了一半发现有点问题 就看看评论有无教程 就看到这个了!
【回复】老哥,提取码错误阿,能再发一遍吗,谢谢了![星星眼]
cool6zzz:
P37的表达式:
X = text.sourceText;
F = Math.round(time * Speed % 1);
L = X.length;
T = time * Speed - StartAt * Speed;
Cursor = " ";
if (F==1 | T>0) Cursor = "|";
if (T>=L) Cursor = " ";
if (T>0) X.substr(0,T) + Cursor
else Cursor
if(F==1 |(T<L & T>0)){Fl="|";}else{Fl=" ";}
substr(0,T) + Fl
【回复】回复 @丶霜语 : https://www.bilibili.com/read/cv18831114?spm_id_from=333.999.0.0
【回复】https://www.bilibili.com/read/cv18831114?spm_id_from=333.999.0.0
【回复】回复 @丶霜痕 :带上似乎发不出来
LittleAsteroid:
居然有效果预览合集,可以直接选对应p,太天使了,谢谢谢谢
【回复】https://www.bilibili.com/read/cv21905239
【回复】AE安装包
https://pan.baidu.com/s/1EdNeTLuBTlyhJwfnhykjug
提取码:4444
偶尔沙雕Gesd:
我改了一下这才是p22表达式
freq = 1.5;
decay = 15;
duration = 0.18;
retard = textIndex*thisComp.frameDuration*1;
t = time - (inPoint + retard);
startVal = 【100,100,100】;
endVal = 【0,0,0】;
if (t < duration){
linear(t,0,duration,startVal,endVal);
}else{
amp = (endVal - startVal)/duration;
w = freq*Math.PI*2;
endVal + amp*(Math.sin((t-duration)*w)/Math.exp(decay*(t-duration))/w);
}
【回复】回复 @丸五 : https://www.bilibili.com/read/cv18831114?spm_id_from=333.999.0.0
【回复】哈喽想问一下为啥startval内行总是在报错
崔巍1999:
请问一下P1属于什么文字效果?谢谢各位大佬,up
【回复】https://www.bilibili.com/read/cv21905239
一Xayah:
P14 搞到头大 中文AE必能用
freq = 1;
decay = 25;
duration = 0.30;
retard = textIndex*thisComp.frameDuration*1;
t = time - (inPoint + retard);
startVal = 【100,100,100】;
endVal = 【0,0,0】;
if (t < duration){
linear(t,0,duration,startVal,endVal);
}else{
amp = (endVal - startVal)/duration;
w = freq*Math.PI*2;
endVal + amp*(Math.sin((t-duration)*w)/Math.exp(decay*(t-duration))/w);
}
【回复】https://www.bilibili.com/read/cv21905239
【回复】【】 英文括号,英文;
琉星想不开:
P4最后一个图片的动画怎么弄成和文字一样丝滑?视频没讲图片怎么操作[笑哭]图片也不像文字点开有个动画能添加
魔女雯子:
p22
freq = 1.5;
decay = 15;
duration = 0.18;
retard = textIndex*thisComp.frameDuration*1;
t = time - (inPoint + retard);
startVal = 【100,100,100】;
endVal = 【0,0,0】;
if (t<duration){
linear(t,0,duration,startVal,endVal);
}else{
amp = (endVal - startVal)/duration;
w = freq*Math.PI*2;
endVal + amp*(Math.sin((t-duration)*w)/Math.exp(decay*(t-duration))/w);
}
【回复】这两行的【】要用英文输入法输
startVal = 【100,100,100】;
endVal = 【0,0,0】
这一行要有小于符号在t和duration之间
if (t duration){
【回复】回复 @魔女雯子 :if (t duration){
小于符号
【回复】为啥我Ae提示我第一行错误阿。
霖汐_Channel:
P14 poppins字体链接:http://www.downcc.com/font/301453.html